64-bit issue - Win7

I’m just getting started with CUDA and I am going through Super Computing for the masses found here

http://www.ddj.com/architect/207200659

When I build the code below using Visual Studio I get this

Error 1 fatal error LNK1112: module machine type ‘x64’ conflicts with target machine type ‘X86’ c:\Users\Michael\Documents\Visual Studio 2008\Projects\cudafun\cudafun\Debug\moveArrays.cu.obj 1 cudafun

I’m using a build rule I found somewhere on the internet(can’t seem to figure out exactly where now).

Everything I have is 64-bit. I’ve even went through and double checked. Visual studio is 64-bit(I double checked to make sure I installed everything), windows 7 is 64-bit and I did install the 64-bit version of CUDA.

I’m guessing some Project option isn’t set right.

[codebox]// moveArrays.cu

//

// demonstrates CUDA interface to data allocation on device (GPU)

// and data movement between host (CPU) and device.

#include <stdio.h>

#include <assert.h>

#include <cuda.h>

int main(void)

{

float *a_h, *b_h; // pointers to host memory

float *a_d, *b_d; // pointers to device memory

int N = 14;

int i;

// allocate arrays on host

a_h = (float *)malloc(sizeof(float)*N);

b_h = (float *)malloc(sizeof(float)*N);

// allocate arrays on device

cudaMalloc((void **) &a_d, sizeof(float)*N);

cudaMalloc((void **) &b_d, sizeof(float)*N);

// initialize host data

for (i=0; i<N; i++) {

  a_h[i] = 10.f+i;

  b_h[i] = 0.f;

}

// send data from host to device: a_h to a_d

cudaMemcpy(a_d, a_h, sizeof(float)*N, cudaMemcpyHostToDevice);

// copy data within device: a_d to b_d

cudaMemcpy(b_d, a_d, sizeof(float)*N, cudaMemcpyDeviceToDevice);

// retrieve data from device: b_d to b_h

cudaMemcpy(b_h, b_d, sizeof(float)*N, cudaMemcpyDeviceToHost);

// check result

for (i=0; i<N; i++)

  assert(a_h[i] == b_h[i]);

// cleanup

free(a_h); free(b_h);

cudaFree(a_d); cudaFree(b_d);

}[/codebox]