Can I pass a thrust::device_vector<float3> to thrust::transform?

Accelerated Computing CUDA CUDA Programming and Performance
1

Currently the transformation is returning all zeros. Any insight would be greatly appreciated! Thanks.

struct Transformer
{

int3 stride_;

Transformer(int3 stride) : stride_(stride)
{
}
host device
int operator()(const float3 & pt)
{
return (
pt.x +
pt.y * stride_.y +
pt.z * stride_.z
);
}
}
##Main code
thrust::host_vector indices(len);

thrust::device_vector pts(len);

thrust::device_vector d_indices(len);
thrust::copy_n(input, len, pts.begin());

thrust::transform(pts.begin(), pts.end(), d_indices.begin(), Transformer({ 250,250,250 }));

2

I don’t get all zeroes:

$ cat t23.cu
#include <thrust/device_vector.h>
#include <thrust/host_vector.h>
#include <thrust/copy.h>
#include <thrust/transform.h>
#include <iostream>

struct Transformer
{

        int3 stride_;

        Transformer(int3 stride) : stride_(stride)
        {
        }
        __host__ __device__
                int operator()(const float3 & pt)
                {
                        return (
                                        pt.x +
                                        pt.y * stride_.y +
                                        pt.z * stride_.z
                               );
                }
};

int main(){
  float3 input[] = { {10.0f,10.0f,10.0f}};
  const int len = sizeof(input)/sizeof(input[0]);
  thrust::host_vector<int> indices(len);

  thrust::device_vector<float3> pts(len);

  thrust::device_vector<int> d_indices(len);
  thrust::copy_n(input, len, pts.begin());

  thrust::transform(pts.begin(), pts.end(), d_indices.begin(), Transformer({ 250,250,250 }));
  thrust::copy_n(d_indices.begin(), len, std::ostream_iterator<int>(std::cout, ","));
  std::cout << std::endl;
}

$ nvcc -std=c++11 -o t23 t23.cu
$ ./t23
5010,
$

In the future, if you are asking for help, please provide a complete code, just as I have done.