--deviceemu by default?

Accelerated Computing CUDA CUDA Programming and Performance
1

Is there anyway to have --deviceemu always passed to the compiler? Maybe something with its interaction with Visual Studio?

I’m not even sure how to attack this, in Windows anyway.

Thanks

2

Sure, you can set it in the custom compiler flags. If you base your project off of the template one, you get debug, release, emudebug and emurelease configurations made for you.