Hi,
How can I fill the square table with this rule: each cell in row has cell in row above value. first row is 0 to N-1. the table is one dimensional.
each row should be compute with parallelism and than synchronize thread and compute next row. for example for N=4 it should at the end looks like:
0 1 2 3 0 1 2 3 0 1 2 3 0 1 2 3
thanks
Hi,
If I understand your problem you have to:
compute index= blockDim.x* blockIdx.x + blockIdx.y
assign each element of the vector as: outVector[index] = index % N (i.e. the modulus operator)
Hope this helps
no, it was an example. in the cell could be other value, for example a,b,c,d. and i can’t compute each cell i must copy from cell above
if W is width than tab[i]=tab[i-W] (for i>=W).
I’ve solved it. Solution:
[codebox]
dim3 block(10,1,1);
dim3 grid(image.size()/(block.x*H),1,1);
go<<<grid,block>>>(out,degree,thre,W,H);
//kernel
global void go(int * out, int degree, int thre, int W, int H){
int x=blockIdx.x * blockDim.x + threadIdx.x;
for(int i=0;i<H;i++){
__syncthreads();
out[i*W+x]=i*W+x;
if(i>0)
out[i*W+x]=out[i*W-W+x];
}
}
[/codebox]