Nvc++ (from nvhpc22.11) ctz error

Accelerated Computing HPC Compilers nvc, nvc++ and nvfortran
1

Dear devs,

I faced an issue/bug with nvc++ (from nvhpc 22.11) about ctz.
Here is a minimal example main.cpp :

#include <stdio.h>

int main() {
	int n = 16;

	printf("Has builin_ctz : %d\n", __has_builtin(__builtin_ctz));

	printf("Use of __builtin_ctz : %d\n", __builtin_ctz(n));

	return 0;
}

This example compiled with nvc++ 22.3 (or 22.1) gives me the following (as expected):

root@local:/test# nvc++ --version

nvc++ 22.1-0 64-bit target on x86-64 Linux -tp haswell
NVIDIA Compilers and Tools
Copyright (c) 2022, NVIDIA CORPORATION & AFFILIATES.  All rights reserved.

root@local:/test# nvc++ -o main ./main.cpp
root@local:/test# ./main
Has builin_ctz : 1
Use of __builtin_ctz : 4

while when compiled with nvc++ 22.11, I got the following wrong results:

root@local:/test# nvc++ --version

nvc++ 22.11-0 64-bit target on x86-64 Linux -tp haswell
NVIDIA Compilers and Tools
Copyright (c) 2022, NVIDIA CORPORATION & AFFILIATES.  All rights reserved.

root@local:/test# nvc++ -o main ./main.cpp
root@local:/test# ./main
Has builin_ctz : 0
Use of __builtin_ctz : 4

This difference disables me from compiling a more complex program using the ctz feature.
Best.

2

Hi D.R.N.O,

Thanks for the report. Seems like whatever caused this issue began with the 22.9 release.

It appears that you have already reported the issue via NVBUGs, which our engineers have received.

-Mat

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