Overload cuBLAS arithmetic for finite fields??

Accelerated Computing CUDA CUDA Programming and Performance
1

Hey experts,

I was wondering if it is possible to overload the cuBLAS arithmetic for finite fields. For example to invert a finite field I wanted to overload the multiply and add operators to do finite field multiplication (using log tables) and addition (xor). Is this possible?

2

probably no, since cublas is closed-source precompiled lib. look at http://cumodp.org/doc/index.html