when compiling some simple Fortran code with an ISHIFT call with pgfortran 17.10:
subroutine shift(s) integer(8) :: s s=ishft(s,21) end subroutine
I see the output:
iliutil.c: case IL_KISHFT:
Do I need to worry about this, or is this just some kind of compiler debugging output that was forgotten to be disabled for the last release?
I did not see this with 17.04, but in fact I saw the same thing with flang for a while (but not any more):