round(float, precision) What is the GPU equivalent??

[Sarnath]

What is the equivalent of the “round(floatNumber, precision)” function in the GPU?

The MSDN documentation of this CPU based function can be found @
ms-help://MS.MSDNQTR.v80.en/MS.MSDN.v80/MS.NETDEVFX.v20.en/cpref2/html/M_System_Math_Round_1_002e4a0f.htm

I could NOT find a GPU equivalent in the programming guide.

Appreciate any help!

Thank you
Best Regards,
Sarnath

[Ocire]

i can’t open the provided link (a strange protocol that is ;-))

however, if this round is something like round(1.23456789,2)=1.23, you could use the following standard functions: round(floatNumber*(10^precision))(10^-precision). i’m assuming, precision is static, so the example would be something like round(1.23456789100.)*0.01.

[Sarnath]

i can’t open the provided link (a strange protocol that is ;-))

I hope you tried to open it in MSDN. IE will not work.

however, if this round is something like round(1.23456789,2)=1.23, you could use the following standard functions: round(floatNumber*(10^precision))(10^-precision). i’m assuming, precision is static, so the example would be something like round(1.23456789100.)*0.01.

Your understanding of round is right. But round has some more intricacies especially when the rounding is based on an adjacent precision value of “5”.

But I think otherwise, your formula really looks coooooool. Thanks.