An question about a cuda program

Dear all,

I have a program like the following:

#include <stdio.h>
#include <stdlib.h>
#include <cuda.h>

using namespace std;

#define BLOCK_SIZE 32
#define GRID_SIZE 14

// Kernel definition
global void VecAdd(float* A, float* C) {
int i = threadIdx.x;
int j = blockIdx.x;
int n = 32*j+i;

    asm(".reg .f32\tt1;\n\t"                // temp reg t1 t2 t3
        ".reg .f32\tt2;\n\t"
        "\tt1, [%0];\n\t"      //
        : : "r" (&A[n]));

    for (int m = 0 ; m < 1000000 ; m++) {
            asm("\tt2, [%0];\n\t" : : "r" (&A[n]));


int main() {
size_t size = BLOCK_SIZEGRID_SIZEsizeof(float);

    float* A = (float*)malloc(size);
    float* C = (float*)malloc(size);

    for (int i = 0 ; i < BLOCK_SIZE*GRID_SIZE ; ++i) {

    float* gA;

    float* gC;

    dim3 grid(GRID_SIZE , 1 , 1);
    dim3 block(BLOCK_SIZE , 1 , 1);

    // Kernel invocation 
    VecAdd<<<grid , block>>>(gA, gC);


    for (int j=0;j<BLOCK_SIZE*GRID_SIZE;++j) {


    return 0;


In kernal function, there is a for loop. I find that when the loop scale under a certain number(may around 300000000, I don’t remember), the running time of this program will be very short(maybe under 5 seconds). When the scale goes up, the running time will be very long(few minutes, I didn’t wait for its ending). In this program, the loop instruction is ‘ld’. Sometimes, when I try other instructions(for example, ‘cvta’), the program even can’t be compiled successfully(no errors, just keep compiling without ending). What’s wrong with the code? Is there anyone know about it?

It might have something to do with loop unrolling. It can only unroll so many loops before the kernel gets to the 2mb limit. This would also explain the long compile times. Try adding “#pragma unroll 1” before the loop to see if disabling this gives you more linear results.

This is just a guess. Hope this helps…

Thank you very much!! It works!!