CUDA_ERROR_INVALID_VALUE when creating tensor maps with swizzling

Accelerated Computing CUDA CUDA Programming and Performance
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1

I’m trying to use tensor maps with swizzling, but any swizzle size that is smaller than the innermost tile size (i.e. 32B swizzle with a 64B tile) returns a CUDA_ERROR_INVALID_VALUE. I can’t find any requirement for this in either the PTX ISA or the cuTensorMapEncodeTiled documentation.

  1. Is this intentional?
  2. If so, is this invariant documented anywhere?

As an example of a failing configuration:

tensorDataType: CU_TENSOR_MAP_DATA_TYPE_FLOAT16
tensorRank: 3
globalDim: [6144, 6144, 1]
globalStrides: [6144, 37748736]
boxDim: [128, 32, 1]
elementStrides: [1, 1, 1]
interleave: CU_TENSOR_MAP_INTERLEAVE_NONE
swizzle: CU_TENSOR_MAP_SWIZZLE_128B
l2Promotion: CU_TENSOR_MAP_L2_PROMOTION_NONE
oobFill: CU_TENSOR_MAP_FLOAT_OOB_FILL_NONE
2

Are you sure that this statement doesn’t apply?

When interleave is CU_TENSOR_MAP_INTERLEAVE_NONE and swizzle is not CU_TENSOR_MAP_SWIZZLE_NONE, the bounding box inner dimension (computed as boxDim[0] multiplied by element size derived from tensorDataType) must be less than or equal to the swizzle size.

It seems like your tensorDataType specifies 2 bytes per element, and your boxDim[0] is 128, so that would result in a product of 256, which is larger than your swizzle size.

3

Ah I was looking at the wrong section then, this seems more relevant to swizzle but is in the interleave section. Appreciate the quick response.

4

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