cudaGetMemInfo Does it work for 64 bits machine

Accelerated Computing CUDA CUDA Programming and Performance
1

Here is my test code:

[codebox]#include <stdio.h>

void test1_b()

{

//int nbytes=100000;

float free_m,total_m,used_m;

size_t *free,*total;

cudaSetDevice(0);

// float3 *d_input,*h_input;

// cudaHostAlloc((void **)&h_input, nbytes, 6);

// cudaHostGetDevicePointer((void **)&d_input, (void *)h_input, 0);

// cudaFreeHost(h_input);

// cudaFree(d_input);

cudaMemGetInfo((size_t*)&free,(size_t*)&total);

free_m =(size_t)free/1048576.0 ;

total_m=(size_t)total/1048576.0;

used_m=(total_m-free_m);

printf ( " mem free %d … %f MB mem total %d…%f MB mem used %f MB\n",free,free_m,total,total_m,used_m);

}

int main()

{

test1_b();

}

[/codebox]

And the result:

mem free 529989632 … 134214136.000000 MB mem total 939196416…895.687500 MB mem used -134213240.000000 MB

The total is Ok, but the free memomry is all over the place. Does it work for 64 bits machine (Linux)

size_t and size_t* are both 8.

2

Hi,

do you tryed to use %ld in printf format?

bye

giammy

3

%ld does not help,the float value is still the same.
Can someone compile this on a 32 bits machine?

4

Ok, Got it to work by changing:

size_t *free,*total;

to

size_t free_t,total_t;

Also, since free is also a linux command, it is a good idea not to use this name.