My apologies if this is redundant, but to the best of my recollection this has not been discussed in these forums previously.
The sigmoid function (or more accurately, the logistic function, as sigmoid functions are a class of functions) 1/ (1 + exp (-x)) can easily be computed with extremely high throughput by making use of the hardware-based computation of reciprocal and exponential base-2 (MUFU.RCP
and MUFU.EX2
machine instructions). This leads to an instruction sequence comprising just four instructions in total, of which two are handled by the multi-function unit.
On some recent architectures, NVIDIA has reduced the throughput of multi-function unit operations relative to the throughput of FFMA
, from 1:4 to 1:8. Having a function implementation based on two MUFU operations seems like a potential bottleneck in that new world. Luckily, a while back (with the Turing architecture, best I know) NVIDIA added a new MUFU.TANH
instruction, and this can be used to compute the sigmoid function with just a single MUFU operation causing throughput to almost double: sigmoid(x) = (1 + tanh (x / 2)) / 2.
Optimizing for performance usually involves trade-offs, and that is also the case here. The classical computation via MUFU.RCP
and MUFU.EX2
is very accurate, with a maximum error of 2 ulps in the positive half-plane and 30 ulps in the negative half-plane (prior to hitting the underflow boundary). The computation via MUFU.TANH
incurs a maximum error of 67 ulps in the positive half-plane. Even worse, in the negative half-plane it suffers from subtractive cancellation, causing relative error and ulp error to grow rapidly ever larger with increasing magnitude of the argument.
Clearly the tanh-based computation should be used only on GPUs whose architecture supports MUFU.TANH
. Below I experimented with a __tanhf()
device function intrinsic that provides both a native implementation and emulation code. The use of the emulation code path results in good performance, but will make the sigmoid computation via __tanhf() achieve about 15% lower throughput than when using the classical computation, as measured on my Turing based Quadro RTX 4000.
/*
Copyright 2023, Norbert Juffa
Redistribution and use in source and binary forms, with or without
modification, are permitted provided that the following conditions
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notice, this list of conditions and the following disclaimer.
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notice, this list of conditions and the following disclaimer in the
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THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS
"AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT
LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR
A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT
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LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,
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(INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE
OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
*/
/* like copysignf(); when first argument is known to be positive */
__forceinline__ __device__ float copysignf_pos (float a, float b)
{
return __int_as_float (__float_as_int (a) | (__float_as_int (b) & 0x80000000));
}
/* device function intrinsic for hyperbolic tangent */
__forceinline__ __device__ float __tanhf (float a)
{
#if (__CUDACC_VER_MAJOR__ >= 11) && (__CUDA_ARCH__ >= 750)
// maxulperr = 133.95290, maxrelerr = 1.1126e-5
float r;
asm ("tanh.approx.f32 %0,%1; \n\t" : "=f"(r) : "f"(a));
#else
// maxulperr = 108.82848, maxrelerr = 9.3450e-6
const float L2E = 1.442695041f; // log2(exp(1))
float e, r, s, t, d;
s = fabsf (a);
t = -L2E * 2.0f * s;
asm ("ex2.approx.ftz.f32 %0,%1;\n\t" : "=f"(e) : "f"(t));
d = e + 1.0f;
asm ("rcp.approx.ftz.f32 %0,%1;\n\t" : "=f"(r) : "f"(d));
r = fmaf (e, -r, r);
if (s < 4.997253418e-3f) r = a;
if (!isnan (a)) r = copysignf_pos (r, a);
#endif
return r;
}
/* compute the sigmoid function 1/(1+exp(-x)) */
__forceinline__ __device__ float my_sigmoidf (float a)
{
#if USE_TANH
return fmaf (0.5, __tanhf (0.5f * a), 0.5f);
#else // USE_TANH
const float L2E = 1.442695041f; // log2(exp(1))
float t, d, e, r;
t = -L2E * a;
asm ("ex2.approx.ftz.f32 %0,%1;\n\t" : "=f"(e) : "f"(t));
d = e + 1.0f;
asm ("rcp.approx.ftz.f32 %0,%1;\n\t" : "=f"(r) : "f"(d));
return r;
#endif // USE_TANH
}