different results why?

Accelerated Computing CUDA CUDA Programming and Performance
1

Why gives the usage with shared memory different output?
Iam on CUDA 2.3, 3.0

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thank you in advance

2

__syncthreads();

sdata[threadIdx.x] = v[i*blockDim.x+threadIdx.x];

__syncthreads();

so simple… External Media

3

Yeah, I’ve forgotten an extra __syncthreads() in a for loop before. Definitely drives you crazy. :)

4

oh yes the hole week…