larger than 64bit integer I want to count with very big integers, larger than 64bit

[batmanzsolti]

(unsigned) long long int provides 64-bits. There is no built-in non-vector integer type that is wider than 64 bits. However, you could easily build your own 128-bit integer type. For example:

typedef struct {

  unsigned long long int lo;

  unsigned long long int hi;

} my_uint128;

my_uint128 add_uint128 (my_uint128 a, my_uint128 b)

{

  my_uint128 res;

  res.lo = a.lo + b.lo;

  res.hi = a.hi + b.hi + (res.lo < a.lo);

  return res;

}

If a higher performance solution is desired, consider mapping a 128-bit integer to a uint4 and using inline PTX for more efficient handling of the carries between the four 32-bit chunks.

Thats exactly what I want. Thank you very much!

More questions: :-)

1.How can I display in decimal number system?

2. If I want to allocate N-element my_uint128 array to my device, I have to use this code?

cudaMalloc( (void**)&deviceArray, (N * sizeof(my_uint128)) )