Hi, I just got into CUDA 10.2, and I am learning the example (0_simple\VectorAdd), now I just type “printf” to see what happened, but it seems like the main function never calls this "global void vectorAdd"
I am using VIsual Studio 2019 to open the .sln file, and it built, but just can not use this printf.
Thank you!
Make sure you have a call to cudaDeviceSynchronize() at the end of your program. The output of printf() is typically buffered, which is also true of CUDA’s device-side printf. cudaDeviceSynchronize() causes the buffer to be flushed, just like one would use fflush(stdout) for the same purpose for host-side printf.
Since you haven’t shown the entire program, there may be other issues with the code that we can’t see.
Thank you njuffa, I am not quite understanding about calling cudaDeviceSynchronize().
The code is as follows
/**
*/
/**
include <stdio.h>
// For the CUDA runtime routines (prefixed with “cuda_”)
include <cuda_runtime.h>
include <helper_cuda.h>
/**
CUDA Kernel Device code
Computes the vector addition of A and B into C. The 3 vectors have the same
number of elements numElements.
*/
global void
vectorAdd(const float *A, const float *B, float *C, int numElements)
{
int i = blockDim.x * blockIdx.x + threadIdx.x;
printf(“%d \n”, i);
if (i < numElements)
{
C[i] = A[i] + B[i];
}
}
/**
Host main routine
*/
int
main(void)
{
// Error code to check return values for CUDA calls
cudaError_t err = cudaSuccess;
// Print the vector length to be used, and compute its size
int numElements = 50000;
size_t size = numElements * sizeof(float);
printf(“[Vector addition of %d elements]\n”, numElements);
// Allocate the host input vector A
float *h_A = (float *)malloc(size);
// Allocate the host input vector B
float *h_B = (float *)malloc(size);
// Allocate the host output vector C
float *h_C = (float *)malloc(size);
// Verify that allocations succeeded
if (h_A == NULL || h_B == NULL || h_C == NULL)
{
fprintf(stderr, “Failed to allocate host vectors!\n”);
exit(EXIT_FAILURE);
}
// Initialize the host input vectors
for (int i = 0; i < numElements; ++i)
{
h_A[i] = rand()/(float)RAND_MAX;
h_B[i] = rand()/(float)RAND_MAX;
}
// Allocate the device input vector A
float *d_A = NULL;
err = cudaMalloc((void **)&d_A, size);
if (err != cudaSuccess)
{
fprintf(stderr, “Failed to allocate device vector A (error code %s)!\n”, cudaGetErrorString(err));
exit(EXIT_FAILURE);
}
// Allocate the device input vector B
float *d_B = NULL;
err = cudaMalloc((void **)&d_B, size);
if (err != cudaSuccess)
{
fprintf(stderr, “Failed to allocate device vector B (error code %s)!\n”, cudaGetErrorString(err));
exit(EXIT_FAILURE);
}
// Allocate the device output vector C
float *d_C = NULL;
err = cudaMalloc((void **)&d_C, size);
if (err != cudaSuccess)
{
fprintf(stderr, “Failed to allocate device vector C (error code %s)!\n”, cudaGetErrorString(err));
exit(EXIT_FAILURE);
}
// Copy the host input vectors A and B in host memory to the device input vectors in
// device memory
printf(“Copy input data from the host memory to the CUDA device\n”);
err = cudaMemcpy(d_A, h_A, size, cudaMemcpyHostToDevice);
if (err != cudaSuccess)
{
fprintf(stderr, “Failed to copy vector A from host to device (error code %s)!\n”, cudaGetErrorString(err));
exit(EXIT_FAILURE);
}
err = cudaMemcpy(d_B, h_B, size, cudaMemcpyHostToDevice);
if (err != cudaSuccess)
{
fprintf(stderr, “Failed to copy vector B from host to device (error code %s)!\n”, cudaGetErrorString(err));
exit(EXIT_FAILURE);
}
// Launch the Vector Add CUDA Kernel
int threadsPerBlock = 256;
int blocksPerGrid =(numElements + threadsPerBlock - 1) / threadsPerBlock;
printf(“CUDA kernel launch with %d blocks of %d threads\n”, blocksPerGrid, threadsPerBlock);
vectorAdd<<<blocksPerGrid, threadsPerBlock>>>(d_A, d_B, d_C, numElements);
err = cudaGetLastError();
if (err != cudaSuccess)
{
fprintf(stderr, “Failed to launch vectorAdd kernel (error code %s)!\n”, cudaGetErrorString(err));
exit(EXIT_FAILURE);
}
// Copy the device result vector in device memory to the host result vector
// in host memory.
printf(“Copy output data from the CUDA device to the host memory\n”);
err = cudaMemcpy(h_C, d_C, size, cudaMemcpyDeviceToHost);
if (err != cudaSuccess)
{
fprintf(stderr, “Failed to copy vector C from device to host (error code %s)!\n”, cudaGetErrorString(err));
exit(EXIT_FAILURE);
}
// Verify that the result vector is correct
for (int i = 0; i < numElements; ++i)
{
if (fabs(h_A[i] + h_B[i] - h_C[i]) > 1e-5)
{
fprintf(stderr, “Result verification failed at element %d!\n”, i);
exit(EXIT_FAILURE);
}
}
printf(“Test PASSED\n”);
// Free device global memory
err = cudaFree(d_A);
if (err != cudaSuccess)
{
fprintf(stderr, “Failed to free device vector A (error code %s)!\n”, cudaGetErrorString(err));
exit(EXIT_FAILURE);
}
err = cudaFree(d_B);
if (err != cudaSuccess)
{
fprintf(stderr, “Failed to free device vector B (error code %s)!\n”, cudaGetErrorString(err));
exit(EXIT_FAILURE);
}
err = cudaFree(d_C);
if (err != cudaSuccess)
{
fprintf(stderr, “Failed to free device vector C (error code %s)!\n”, cudaGetErrorString(err));
exit(EXIT_FAILURE);
}
// Free host memory
free(h_A);
free(h_B);
free(h_C);
printf(“Done\n”);
return 0;
}
Have a look at this section of the Programming Guide:
Thank you rs277, I cannot believe that I restarted my computer, and it is good now.
